94 lines
4.3 KiB
Python
94 lines
4.3 KiB
Python
"""方案评估器: 对 (case, plan) 做硬件约束校验 + 时延评估 + 瓶颈分析.
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评估模式入口: 用户自带实现方案 (ImplPlan), 软件评估其在 NPU 上的
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各级硬件时延、流水情况与瓶颈, 并做可行性校验.
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"""
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from __future__ import annotations
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from .hardware import NpuSpec, ASCEND950PR
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from .models import BmmCase, ImplPlan, EvalResult
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from .timing import bound_type_of
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from .branches.merge_batch import MergeBatchBranch
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from .branches.iter_batch import IterBatchBranch
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from .branches.to_matmul import ToMatmulBranch
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from .branches.special import SpecialBranch
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from .branches.stream_k import StreamKBranch
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from .branches.asw_basic import AswBasicBranch
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_BRANCH_EVAL = {
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"MergeBatch": MergeBatchBranch,
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"IterBatch": IterBatchBranch,
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"转Matmul": ToMatmulBranch,
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"特殊分支": SpecialBranch,
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"StreamK": StreamKBranch,
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"ASW_Basic": AswBasicBranch,
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"ASW_Basic_降核": AswBasicBranch,
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}
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class PlanEvaluator:
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def __init__(self, spec: NpuSpec = ASCEND950PR):
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self.spec = spec
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def evaluate(self, case: BmmCase, plan: ImplPlan) -> EvalResult:
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res = EvalResult(case=case, plan=plan)
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# 1) 硬件约束校验
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violations = self._check_constraints(case, plan)
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res.feasible = not violations
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res.violations = "; ".join(violations)
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# 2) 时延评估 (按方案分支调用对应模型)
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branch_cls = _BRANCH_EVAL.get(plan.branch)
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if branch_cls is None:
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res.advice = (f"分支 {plan.branch!r} 的评估模型待后续迭代; "
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f"当前支持: {sorted(_BRANCH_EVAL)}")
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return res
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timing = branch_cls(self.spec).evaluate(case, plan)
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res.timing = timing
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res.bound_type = bound_type_of(timing.bottleneck)
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# 3) 瓶颈分析建议
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res.advice = self._advice(case, plan, res)
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return res
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# ------------------------------------------------------------------
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def _check_constraints(self, case: BmmCase, plan: ImplPlan) -> list:
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"""约束校验: 委托给 constraints.py 单一约束源 (与生成同源, issue#5/#6)."""
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from .constraints import check_plan_constraints
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return check_plan_constraints(case, plan, self.spec)
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# ------------------------------------------------------------------
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def _advice(self, case: BmmCase, plan: ImplPlan, res: EvalResult) -> str:
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t = res.timing
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tips = []
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if not res.feasible:
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tips.append("方案违反硬件约束, 需先修正: " + res.violations)
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bn = t.bottleneck
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if bn == "MTE2_GM":
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tips.append("瓶颈在 GM 搬入: 可考虑增大 tile 提升 dValue/单核搬移量, "
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"或利用 L2 驻留吸收重复读 (MergeBatch/ASW swizzle 方向)")
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elif bn == "MTE2_L2":
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tips.append("瓶颈在 L2 重复读: 优化核间分配/swizzle 窗口压低活跃工作集")
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elif bn == "MMAD":
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tips.append("瓶颈在 Cube 计算: 已接近理论算力上限, 检查是否有冗余计算 "
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"(MergeBatch 交叉项) 可消除")
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elif bn == "FIXPIPE":
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if plan.branch == "StreamK":
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# StreamK 部分和按 L0C dtype 4B 防精度丢失, 不随 C 的 fp16/fp8 转换,
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# dtype 减半提示不适用 (issue#14); 写账已并入归约, 需查归约侧配置
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tips.append("瓶颈标注在 Fixpipe: StreamK 的部分和写出已并入归约计账 "
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"(4B 防精度丢失, 不可随 C dtype 减半), 请核查 L2 写口/"
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"归约并行度(grid_K) 设置")
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else:
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tips.append("瓶颈在 Fixpipe 写出: 检查输出 dtype (fp16/fp8 可减半写出量), "
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"或评估输出驻留 L2 异步回写策略")
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elif bn == "REDUCE":
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tips.append("瓶颈在 StreamK 归约 (串行追加): 可增大 grid_K 摊薄归约 "
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"或核对确定性要求是否允许 StreamK")
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if plan.branch == "MergeBatch" and plan.k_l1 < case.k:
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tips.append("警告: MergeBatch 处于 L1 绑定情形 (k_L1<K), 理论证明其恒劣于 "
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"IterBatch (v1.1 §4.4), 建议改用 IterBatch")
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return " | ".join(tips) if tips else "方案合理, 流水均衡"
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