Fix review issues #11-#16: StreamK fixpipe 单次计账 / K=1 AIV单缓冲方案 / MergeBatch b0 L0A/L0B 上限+路由可行回退 / advice-StreamK / 输入校验 / .gitignore+死代码清理
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@@ -94,10 +94,14 @@ class MergeBatchBranch(Branch):
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b = case.batch_c
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b_core = b // s.aic_num
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# Step 1: 合并数 b0 (L0C + 算存比双上限, 尽量取 b_core 的因子)
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# Step 1: 合并数 b0 (L0C + L0A/L0B + 算存比 + b_core 四类上限, 尽量取 b_core 的因子)
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# L0A/L0B 上限 (issue#13): 合并 tile = (b0*M)x(b0*N), base_k 有 16 (fractal) 硬底,
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# 须满足 b0*M*16*dt*2 <= L0A 且 b0*N*16*dt*2 <= L0B, 否则合并后 L0 tile 无法驻留.
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b0_l0c = math.sqrt(s.l0c_bytes / (2 * m * n * 4))
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b0_ai = s.r16 * (m + n) / (2 * m * n)
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b0_max = int(min(b0_l0c, b0_ai, b_core))
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b0_l0a = s.l0a_bytes / (2 * m * s.fractal * dt)
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b0_l0b = s.l0b_bytes / (2 * n * s.fractal * dt)
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b0_max = int(min(b0_l0c, b0_ai, b0_l0a, b0_l0b, b_core))
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b0 = max(MIN_B0, self._factor_floor(b_core, b0_max))
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# Step 2: L0 级 K 粒度 k_L0
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@@ -24,11 +24,14 @@ class SpecialBranch(Branch):
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c1 = case.k <= 1
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checks = [ConditionCheck("1_K<=1 (Cube 无用)", c1, f"K={case.k}")]
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if case.k == 1:
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# K=1 触发 AIV 通路需 B >= 2*AIV核数 且单 batch 输入输出能驻留 UB
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c2 = case.batch_c >= 2 * self.spec.aiv_num
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# K=1 的 AIV 通路恒可用 (issue#12): B>=2*AIV 开 UB 乒乓; B<128 退化为
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# AIV 单缓冲 (无乒乓, 逐 batch 串行搬入), 不再是无方案空洞.
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b = case.batch_c
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pingpong = b >= 2 * self.spec.aiv_num
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mode = "UB乒乓" if pingpong else "AIV单缓冲(逐batch串行, B<2*AIV)"
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checks.append(ConditionCheck(
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"2_K=1的AIV触发: B >= 2*AIV核数 (开UB乒乓)",
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c2, f"B={case.batch_c} vs {2*self.spec.aiv_num}"))
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"2_K=1的AIV通路: 恒可用 (B>=128 开UB乒乓, 否则单缓冲)",
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True, f"B={b}, 模式={mode}"))
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return checks
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# ------------------------------------------------------------------
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@@ -36,11 +39,15 @@ class SpecialBranch(Branch):
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s = self.spec
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if case.k == 0:
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sub = "K=0纯写值"
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mode = ""
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note = "无任何计算, C=bias 或 0, 纯 AIV 写值; 按行均分到 AIV 核"
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else:
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sub = "K=1逐元素乘"
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note = ("退化为 C=A⊙B 无累加深度, Cube 16x16x16 粒度浪费 15/16; "
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"走 AIV 通路 GM->UB->Mul->GM, UB 乒乓")
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pingpong = case.batch_c >= 2 * s.aiv_num
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mode = "UB乒乓" if pingpong else "AIV单缓冲"
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note = (f"退化为 C=A⊙B 无累加深度, Cube 16x16x16 粒度浪费 15/16; "
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f"走 AIV 通路 GM->UB->Mul->GM, {mode} "
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f"({'B>=2*AIV 双batch乒乓流水' if pingpong else 'B<2*AIV 逐batch单缓冲串行'})")
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return ImplPlan(
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case_id=case.case_id, branch=self.name,
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used_core_num=s.aiv_num, # 用 AIV 核
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@@ -48,7 +55,8 @@ class SpecialBranch(Branch):
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core_map="AIV 核间按行均分 (无 Cube tile 概念)",
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b_core=0, merge_b0=1,
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single_core_m=0, single_core_n=0, single_core_k=case.k,
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k_l1=0, b_l1=1, l1_form="UB驻留(AIV)",
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k_l1=0, b_l1=1,
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l1_form="UB驻留(AIV)" if case.k == 0 else "UB驻留(AIV) " + mode,
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base_m=0, base_n=0, base_k=0,
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l2_policy_in="allocate", l2_policy_out="direct_gm",
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swizzle_w=0, workspace_bytes=0,
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@@ -145,13 +145,14 @@ class StreamKBranch(Branch):
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t_mmad = t_mmad_tile / grid_k
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t_mte2 = t_mte2_tile / grid_k
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# 归约: 部分和 4B 驻留 L2, AIV 归约 (含最终按 C dtype 写回)
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# 归约: 部分和 4B 驻留 L2, AIV 归约 (含部分和写/读回/求和/最终按 C dtype 写回)
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# 口径 (issue#11): 归约整体为串行追加 (t_drain=t_reduce, reduce_serial=True),
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# 部分和写出已计入 eval_streamk_reduce 的 t_write_partial —— 稳态 Fixpipe 不再
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# 重复计账. 此前按 grid_k*tile*4B/单核带宽份额另计一次, 既重复计账又把整组
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# 部分和串行压到单核写口, 高估 grid_k 倍 (streamk_demo 曾虚高到 55us/FIXPIPE).
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t_reduce = eval_streamk_reduce(tile_elems, grid_k, out_b, s)
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# Fixpipe: 部分和写出按 4B (L0C dtype, 防精度丢失), 驻留 L2.
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# 最终归约结果的 C dtype 写回已在 t_reduce 内计, 此处不重复 (issue#9 口径对齐).
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fix_bytes = grid_k * tile_elems * 4
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t_fix = fix_bytes / s.bw_l2_pc
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fix_bytes = 0.0
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t_fix = 0.0
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flops_pc = 2.0 * tile_elems * k / grid_k
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gm_bytes = k * (2 * math.sqrt(tile_elems)) * dt / grid_k
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